Let any parity vector v have length l(v).
Call A its longest repeated substring (with wraparound), with length l(A).
We already know that vectors for which l(A) > 0.38\, l(v) are not integer cycles; if they were, the difference between the cycle members associated with AB and AC would be an integer.
\cfrac{\beta(AC)}{\delta(v)}-\cfrac{\beta(AB)}{\delta(v)} = \cfrac{2^{l(A)}\, (\beta(C)-\beta(B))}{\delta(v)}
We can cancel the 2s without affecting integrality. But then the result is not, in fact, an integer, because itâs less than one (and not zero):
\cfrac{\beta(C) - \beta(B)}{\delta(v)} < \cfrac{3^{l(v)-l(A)}}{2^{l(v)}\, l(v)^{-13.3}} < \cfrac{3^{0.62\,l(v)}}{2^{l(v)}}\, l(v)^{13.3} \ll 1
The first step above is justified by the worst case where B=1^* 0 and C=0 1^* (numerator upper bound), and by Rhin (denominator lower bound).
But what if l(A) is short, even as short as \lfloor \log l(v) \rfloor? Then we have fewer 2s to cancel, but on the other hand, the worst case B=1^* 0, C=0 1^* canât happen, because AC (and therefore v) would have an LRS longer than l(A).
Question.
Among those v with a specified LRS of length l(A), how big can \beta(C)-\beta(B) get?
The very, very rough graph below shows the case for l(v)=100, with different values of l(A) along the x-axis.
The blue line shows the (approximate) maximum possible \beta(C)-\beta(B) at each l(A). When the difference is less than \delta(v) (the dashed gray line), v is certifiably not an integer cycle. Anything above the dashed gray line is up for grabs.
The green line shows 3^{l(v)-l(A)}, a true upper bound on \beta(C)-\beta(B), but one that is very loose for small l(A).
Notice that for small l(v)=100, we cannot rule out vectors with small LRSs as integer cycles (blue line above gray dashed line). But strange things happen at small values of l(v), and we donât know what this chart looks like asymptotically.
How high does the blue curve ever get, in terms of l(v) and l(A), for sufficiently long v?




