Yes, you can say that (you can skip the \log_2(\frac{x}{2}) intermediate step and it would be true for x>1). It still seems too high to be able to do something with it.
Yes, you can say that (you can skip the \log_2(\frac{x}{2}) intermediate step and it would be true for x>1). It still seems too high to be able to do something with it.